x[x-3(6-3x)+2x]=6(2x^2-1)

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Solution for x[x-3(6-3x)+2x]=6(2x^2-1) equation:


Simplifying
x[x + -3(6 + -3x) + 2x] = 6(2x2 + -1)
x[x + (6 * -3 + -3x * -3) + 2x] = 6(2x2 + -1)
x[x + (-18 + 9x) + 2x] = 6(2x2 + -1)

Reorder the terms:
x[-18 + x + 9x + 2x] = 6(2x2 + -1)

Combine like terms: x + 9x = 10x
x[-18 + 10x + 2x] = 6(2x2 + -1)

Combine like terms: 10x + 2x = 12x
x[-18 + 12x] = 6(2x2 + -1)
[-18 * x + 12x * x] = 6(2x2 + -1)
[-18x + 12x2] = 6(2x2 + -1)

Reorder the terms:
-18x + 12x2 = 6(-1 + 2x2)
-18x + 12x2 = (-1 * 6 + 2x2 * 6)
-18x + 12x2 = (-6 + 12x2)

Add '-12x2' to each side of the equation.
-18x + 12x2 + -12x2 = -6 + 12x2 + -12x2

Combine like terms: 12x2 + -12x2 = 0
-18x + 0 = -6 + 12x2 + -12x2
-18x = -6 + 12x2 + -12x2

Combine like terms: 12x2 + -12x2 = 0
-18x = -6 + 0
-18x = -6

Solving
-18x = -6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-18'.
x = 0.3333333333

Simplifying
x = 0.3333333333

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